Chlorpheniramine Maleate
(klor'' fen ir' a meen mal' ee ate).
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C16H19ClN2·C4H4O4 390.86

2-Pyridinepropanamine, -(4-chlorophenyl)-N,N-dimethyl-, (Z)-2-butenedioate (1:1).
2-[p-Chloro--[2-(dimethylamino)ethyl]benzyl]pyridine maleate (1:1) [113-92-8].
» Chlorpheniramine Maleate contains not less than 98.0 percent and not more than 100.5 percent of C16H19ClN2·C4H4O4, calculated on the dried basis.
Packaging and storage— Preserve in tight, light-resistant containers.
USP Reference standards 11
USP Chlorpheniramine Maleate RS Click to View Structure
Identification, Infrared Absorption 197K.
Melting range 741: between 130 and 135.
Loss on drying 731 Dry it at 105 for 3 hours: it loses not more than 0.5% of its weight.
Residue on ignition 281: not more than 0.2%.
Related compounds—
Test preparation— Dissolve about 200 mg of Chlorpheniramine Maleate in 5 mL of methylene chloride, and mix.
Chromatographic system (see Chromatography 621) The gas chromatograph is equipped with a flame-ionization detector and a 1.2-m × 4-mm glass column containing 3% phase G3 on support S1AB. The column temperature is maintained at about 190, and the injection port and detector temperatures are both maintained at about 250. The carrier gas is dry helium, flowing at a rate adjusted to obtain a retention time of 4 to 5 minutes for the main peak. Chromatograph the Test preparation, record the chromatogram, and determine the peak area as directed for Procedure: the tailing factor for the chlorpheniramine maleate peak is not more than 1.8.
Procedure— Inject a volume (about 1 µL) of the Test preparation into the chromatograph. Record the chromatogram for a total time of not less than twice the retention time of the chlorpheniramine peak, and measure the areas of the peaks. The total relative area of all extraneous peaks (except that of the solvent peak and maleic acid, if observed) does not exceed 2.0%.
Assay— Dissolve about 500 mg of Chlorpheniramine Maleate, accurately weighed, in 20 mL of glacial acetic acid. Add 2 drops of crystal violet TS, and titrate with 0.1 N perchloric acid VS. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N perchloric acid is equivalent to 19.54 mg of C16H19ClN2·C4H4O4.
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Monograph Domenick Vicchio, Ph.D.
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