【药物名称】FFC14A, KP-1019(anhydrous), IndH(RuInd2Cl4), KP-692, HInd(RuInd2Cl4)
化学结构式(Chemical Structure):
参考文献No.147008
标题:HInd(RuInd2Cl4)
作者:Berger, M.R.; Galeano, A.; Seelig, M.; Keppler, B.K.
来源:Drugs Fut 1990,15(10),992
合成路线图解说明:

According to the reaction commercially available RuCl3 is purified by refluxing with EtOH and HCl to give a solution of Ru(III), which is then reacted with indazole (Ind) in 1N HCl to give the complex HInd(RuInd2Cl4).

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