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Add the following:
» Piperazine Adipate contains not less than 98.0 percent and not more than 101.0 percent of C4H10N2·C6H10O4, calculated on the anhydrous basis.
Packaging and storage
Preserve in well-closed containers, and store at room temperature.
Labeling
Label it to indicate that it is for veterinary use only.
USP Reference standards
USP Piperazine Adipate RS.
Identification
B:
In the test for Chromatographic purity, the principal spot in the chromatogram obtained from Test solution 2 observed after spraying with the ninhydrin solutions corresponds in RF value, color, and size to that in the chromatogram obtained from Standard solution 1.
C:
To 10 mL of a 1 in 20 solution of it add 5 mL of hydrochloric acid, and extract with three 10-mL portions of ether. Evaporate the combined ether extracts to dryness, wash the residue with water, and dry at 105
Water, Method I
Residue on ignition
Chromatographic purity
Solvent
Prepare a mixture of 13.5 N ammonium hydroxide and dehydrated alcohol (3:2).
Test solution 1
Prepare a solution of Piperazine Adipate in Solvent containing 100 mg per mL.
Test solution 2
Mix 1 mL of Test solution 1 and 9 mL of Solvent.
Standard solution 1
Prepare a solution of USP Piperazine Adipate RS in Solvent containing 10 mg per mL.
Standard solution 2
Prepare a solution of ethylenediamine in Solvent containing 0.25 mg per mL.
Standard solution 3
Prepare a solution of triethylenediamine in Solvent containing 0.25 mg per mL.
Resolution solution
Prepare a solution in Solvent containing 0.25 mg of triethylenediamine and 10 mg of Piperazine Adipate per mL.
Procedure
Separately apply 5-µL portions of Test solution 1, Test solution 2, Standard solution 1, Standard solution 2, Standard solution 3, and the Resolution solution to a suitable thin-layer chromatographic plate (see Chromatography
Assay
Dissolve about 100 mg of Piperazine Adipate, accurately weighed, in 10 mL of glacial acetic acid, heating gently if necessary. Add 60 mL of glacial acetic acid and 0.25 mL of p-naphtholbenzein TS, and titrate with 0.1 N perchloric acid until the brownish-yellow color of the solution turns green. Each mL of 0.1 N perchloric acid is equivalent to 11.61 mg of C4H10N2·C6H10O4.
Auxiliary Information
Please check for your question in the FAQs before contacting USP.
USP32NF27 Page 3314
Pharmacopeial Forum: Volume No. 33(6) Page 1201
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