Noscapine
413.421(3H)-Isobenzofuranone, 6,7-dimethoxy-3-(5,6,7,8-tetrahydro-4-methoxy-6-methyl-1,3-dioxolo[4,5-g]isoquinolin-5-yl), [S-(R*,S*)]-.
Narcotine
[128-62-1].» Noscapine contains not less than 99.0 percent and not more than 100.5 percent of C22H23NO7, calculated on the anhydrous basis.
Packaging and storage—
Preserve in well-closed containers.
Identification—
A:
Infrared Absorption 
197K
—Do not dry specimens.
197K—Do not dry specimens.
C:
Place about 100 mg in a small porcelain dish, add a few drops of sulfuric acid, and stir: a greenish yellow solution is produced, and on warming it becomes red and then turns violet.
Specific rotation 781S:
between +42
and +48.
781S:
between +42 and +48.
Test solution:
20 mg per mL, in 0.1 N hydrochloric acid.
Water, Method I 921:
not more than 1.0%.
921:
not more than 1.0%.
Residue on ignition 281:
not more than 0.1%.
281:
not more than 0.1%.
Chloride 221—
A 700-mg portion shows no more chloride than corresponds to 0.20 mL of 0.020 N hydrochloric acid (0.02%).
221—
A 700-mg portion shows no more chloride than corresponds to 0.20 mL of 0.020 N hydrochloric acid (0.02%).
Limit of morphine—
Dissolve 100 mg in 10 mL of 0.1 N hydrochloric acid. To 1.0 mL of this solution add 5.0 mL of diluted ferricyanide reagent (prepared by dissolving 0.50 g of potassium ferricyanide in 50 mL of water, adding 0.50 mL of ferric chloride TS, and diluting 5.0 mL of the resulting solution to 25.0 mL): no blue or dark green color develops within 1 minute.
Ordinary impurities 466—
466—
Test solution:
chloroform.
Standard solution:
chloroform.
Eluant:
a mixture of ethyl acetate and ether (80:20).
Visualization:
17; then examine the plate immediately.
Limits—
The sum of the intensities of all secondary spots obtained from the Test solution corresponds to not more than 1.0%.
Assay—
Dissolve about 1.5 g of Noscapine, accurately weighed, in 25 mL of glacial acetic acid. Add 25 mL of dioxane and 5 drops of crystal violet TS, and titrate with 0.1 N perchloric acid VS to a blue endpoint. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N perchloric acid is equivalent to 41.34 mg of C22H23NO7.
Auxiliary Information—
Please check for your question in the FAQs before contacting USP.
| Topic/Question | Contact | Expert Committee |
| Monograph | Clydewyn M. Anthony, Ph.D.
Scientist 1-301-816-8139 |
(MDCCA05) Monograph Development-Cough Cold and Analgesics |
| Reference Standards | Lili Wang, Technical Services Scientist 1-301-816-8129 RSTech@usp.org |
USP32–NF27 Page 3120