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Nortriptyline Hydrochloride
1-Propanamine, 3-(10,11-dihydro-5H-dibenzo[a,d]cyclohepten-5-ylidene)-N-methyl-, hydrochloride. 10,11-Dihydro-N-methyl-5H-dibenzo[a,d]cycloheptene-D5, » Nortriptyline Hydrochloride contains not less than 97.0 percent and not more than 101.5 percent of C19H21N·HCl, calculated on the dried basis.
Packaging and storage
Preserve in tight, light-resistant containers.
Identification
Solution:
50 mg per mL.
Medium:
chloroform.
B:
Ultraviolet Absorption
Solution:
10 µg per mL.
Medium:
methanol.
Absorptivities at 239 nm, calculated on the dried basis, do not differ by more than 3.0%.
C:
It responds to the tests for Chloride
Melting range, Class I
Loss on drying
Residue on ignition
Heavy metals, Method II
Chromatographic purity
Adsorbent:
chromatographic silica gel mixture.
Test solution
Transfer about 250 mg of Nortriptyline Hydrochloride, accurately weighed, to a 10-mL volumetric flask. Dissolve in and dilute with methanol to volume, and mix.
Standard solutions
Dissolve an accurately weighed quantity of USP Nortriptyline Hydrochloride RS in methanol, and dilute quantitatively, and stepwise if necessary, with methanol to obtain a solution having a known concentration of about 25.0 mg per mL (Standard solution A). Dilute appropriate portions of this solution with methanol to obtain Standard solutions B, C, D, E, and F having known concentrations of 125, 75, 50, 25, and 12.5 µg per mL, respectively. The final concentrations of Standard solutions B, C, D, E, and F represent 0.5%, 0.3%, 0.2%, 0.1%, and 0.05% of Standard solution A concentration, respectively.
Application volume:
5 µL.
Developing solvent system:
a mixture of acetonitrile, methanol, and ammonium hydroxide (10:1:1).
Procedure
Apply equal volumes of the Test solution and Standard solutions A, B, C, D, E, and F as directed in Ordinary Impurities
Assay
Dissolve about 600 mg of Nortriptyline Hydrochloride, accurately weighed, in 50 mL of glacial acetic acid, add 10 mL of mercuric acetate TS, and titrate with 0.1 N perchloric acid VS, determining the endpoint potentiometrically. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N perchloric acid is equivalent to 29.98 mg of C19H21N·HCl.
Auxiliary Information
Please check for your question in the FAQs before contacting USP.
Chromatographic Column
USP32NF27 Page 3118
Chromatographic columns text is not derived from, and not part of, USP 32 or NF 27.
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