Panthenol (pan' the nol). C9H19NO4205.25 Butanamide, 2,4-dihydroxy-N-(3-hydroxypropyl)-3,3-dimethyl-, (±)-; (±)-2,4-Dihydroxy-N-(3-hydroxypropyl)-3,3-dimethylbutyramide; (±)-Pantothenyl alcohol [16485-10-2]. DEFINITION Panthenol is a racemic mixture of the dextrorotatory and levorotatory isomers of panthenol. It contains NLT 99.0% and NMT 102.0% of racemic panthenol (C9H19NO4), calculated on the dried basis. IDENTIFICATION • B. Sample solution: 100 mg/mL of Panthenol Analysis: To 1 mL of the Sample solution add 5 mL of 1 N sodium hydroxide and 1 drop of cupric sulfate TS, and shake vigorously. Acceptance criteria: A deep blue color develops. • C. Sample solution: 10 mg/mL of Panthenol Analysis: To 1 mL of the Sample solution add 1 mL of 1 N hydrochloric acid, and heat on a steam bath for 30 min. Cool, add 100 mg of hydroxylamine hydrochloride, and add 5 mL of 1 N sodium hydroxide. Allow to stand for 5 min, then adjust with 1 N hydrochloric acid to a pH of 2.53.0, and add 1 drop of ferric chloride TS. Acceptance criteria: A purplish red color develops. ASSAY • Procedure 0.1 M potassium biphthalate: Transfer 20.42 g of potassium biphthalate into a 1000-mL volumetric flask, and add sufficient glacial acetic acid to dissolve. If necessary, warm the mixture on a steam bath to achieve complete solution, observing precautions against absorption of moisture. Cool to room temperature, and dilute with glacial acetic acid to volume. Sample: 400 mg of Panthenol Blank: Proceed as directed in the Analysis, omitting the Sample. Titrimetric system (See Titrimetry 541.) Mode: Residual titration Titrant: 0.1 N perchloric acid VS Back-titrant: 0.1 M potassium biphthalate Endpoint detection: Visual Analysis: Transfer the Sample to a 300-mL flask fitted to a reflux condenser by means of a standard-taper glass joint, add 50.0 mL of Titrant, and reflux for 5 h. Cool, observing precautions to prevent atmospheric moisture from entering the condenser, and rinse the condenser with glacial acetic acid, collecting the rinsings in the flask. To the flask add 5 drops of crystal violet TS, and titrate with the Back-titrant to a blue-green endpoint. Perform the Blank determination. Calculate the percentage of panthenol (C9H19NO4) in the Sample taken: Result = {[(VB VS) × M × F]/W} × 100
Acceptance criteria: 99.0%102.0% on the dried basis IMPURITIES • Residue on Ignition 281: NMT 0.1% • Limit of Aminopropanol Sample: 10 g of Panthenol Blank: 25 mL of water Titrimetric system (See Titrimetry 541.) Mode: Direct titration Titrant: 0.01 N sulfuric acid VS Endpoint detection: Visual Analysis: Dissolve the Sample in 25 mL of water, and add bromothymol blue TS. Titrate with the Titrant to a yellow endpoint. Perform the Blank determination. Calculate the percentage of aminopropanol in the Sample taken: Result = {[(VS VB) × N × F]/W} × 100
Acceptance criteria: NMT 0.10% SPECIFIC TESTS • Melting Range, Class I 741: 64.568.5 • Optical Rotation, Specific Rotation 781S Sample solution: 50 mg/mL in water Acceptance criteria: 0.05 to +0.05 • Loss on Drying 731: Dry a sample in a vacuum over phosphorus pentoxide at 56 for 4 h: it loses NMT 0.5% of its weight. ADDITIONAL REQUIREMENTS • Packaging and Storage: Preserve in tight containers. Auxiliary Information Please check for your question in the FAQs before contacting USP.
USP35NF30 Page 4208 Chromatographic Column Chromatographic columns text is not derived from, and not part of, USP 35 or NF 30. |