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Stanozolol
(stan oh' zoe lol).
2¢H-Androst-2-eno[3,2-c]pyrazol-17-ol, 17-methyl-, (5 17-Methyl-2¢H-5 » Stanozolol contains not less than 98.0 percent and not more than 100.5 percent of C21H32N2O, calculated on the dried basis.
Packaging and storage
Preserve in tight, light-resistant containers.
Identification
B:
Ultraviolet Absorption
Solution:
50 µg per mL.
Medium:
alcohol.
Absorptivities at 224 nm, calculated on the dried basis, do not differ by more than 3.0%.
Loss on drying
Chromatographic purity
Standard dilutions
Dissolve an accurately weighed quantity of USP Stanozolol RS in a mixture of chloroform and methanol (9:1) to obtain a solution having a known concentration of about 20 mg per mL. Dilute this solution with the same medium to obtain Standard dilutions having known concentrations of about 50, 100, 200, and 400 µg per mL, respectively.
Procedure
Score a 20- × 20-cm thin-layer chromatographic plate coated with a 0.25-mm layer of chromatographic silica gel mixture (binder-free) into channels 10 mm wide. Apply 10-µL portions, in two 5-µL increments, of a test solution prepared by dissolving Stanozolol in a mixture of chloroform and methanol (9:1) to obtain a solution containing about 20 mg per mL, and of each of the four Standard dilutions in the center of the channels at points about 2.5 cm from one edge of the plate. Develop the plate in a suitable chamber, lined with filter paper and previously equilibrated with 200 mL of a mixture of chloroform and methanol (188:12), for 15 minutes, taking care to ensure that the filter paper has been wetted completely with the solvent mixture. Allow the plate to develop until the solvent front has moved about 15 cm above the line of application. Remove the plate, and allow the solvent to evaporate completely. Spray it with 20% sulfuric acid, and heat in an oven at 100
Assay
Dissolve about 700 mg of Stanozolol, accurately weighed, in 50 mL of glacial acetic acid, add 1 drop of crystal violet TS, and titrate with 0.1 N perchloric acid VS to a green endpoint. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N perchloric acid is equivalent to 32.85 mg of C21H32N2O.
Auxiliary Information
Please check for your question in the FAQs before contacting USP.
USP35NF30 Page 4684
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