Antimony Potassium Tartrate
(an' ti moe'' nee poe tas' ee um tar' trate).
Antimonate(2-), bis[µ-[2,3-dihydroxybutanedioato(4-)-O1,O2:O3,O4]]-di-, dipotassium, trihydrate, stereoisomer.
Dipotassium bis[µ-[l-(+)-tartrato(4-)]]diantimonate(2-) trihydrate [28300-74-5].
Anhydrous 613.82 [11071-15-1].
» Antimony Potassium Tartrate contains not less than 99.0 percent and not more than 103.0 percent of C8H4K2O12Sb2·3H2O.
Packaging and storage Preserve in well-closed containers.
Completeness of solution 641: meets the requirements, using a 750-mg specimen and water as the solvent.
A: When heated to redness, it chars, emits an odor resembling that of burning sugar, and leaves a blackened residue. This residue has an alkaline reaction, and when a small fragment of it is held in a nonluminous flame, the flame is tinted violet.
B: In a solution (1 in 20), acidified with hydrochloric acid, hydrogen sulfide TS produces an orange-red precipitate, which is soluble in ammonium sulfide TS and in 1 N sodium hydroxide.
C: It responds to the test for Tartrate 191.
Acidity or alkalinity Dissolve 1.0 g in 50 mL of carbon dioxide-free water, and titrate with 0.010 N hydrochloric acid or 0.010 N sodium hydroxide to a pH of 4.5: not more than 2.0 mL is required.
Loss on drying 731 Dry it at 105 to constant weight: it loses not more than 2.7% of its weight.
Arsenic Dissolve 100 mg in 5 mL of hydrochloric acid. Add 10 mL of a recently prepared solution of 20 g of stannous chloride in 30 mL of hydrochloric acid. Mix, transfer to a color-comparison tube, and allow to stand for 30 minutes. Viewed downward over a white surface, the color of the solution appears no deeper than that of a blank to which has been added 15 µg of arsenic (0.015%).
Lead 251: not more than 0.002%.
Assay Dissolve about 500 mg of Antimony Potassium Tartrate, accurately weighed, in 50 mL of water, add 5 g of potassium sodium tartrate, 2 g of sodium borate, and 3 mL of starch TS, and immediately titrate with 0.1 N iodine VS to the production of a persistent blue color. Each mL of 0.1 N iodine is equivalent to 16.70 mg of C8H4K2O12Sb2·3H2O.