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Floxuridine
(flox ure' i deen).
» Floxuridine contains not less than 98.5 percent and not more than 101.0 percent of C9H11FN2O5, calculated on the dried basis.
Packaging and storage
Preserve in tight, light-resistant containers. Store at 25
Labeling
Where it is intended for use in preparing injectable dosage forms, the label states that it is sterile or must be subjected for further processing during the preparation of injectable dosage forms.
Identification
B:
Ultraviolet Absorption
Solution:
20 µg per mL.
Medium:
0.1 N potassium hydroxide.
Absorptivities at 268 nm, calculated on the dried basis, do not differ by more than 3.0%.
C:
Dissolve about 200 mg in 10 mL of water, and add a few drops of bromine TS: the bromine color is discharged.
Melting range, Class I
Loss on drying
Residue on ignition
Limit of fluoride ions
[noteUse plasticware throughout this test. ]
pH 5.25 Buffer
Dissolve 110 g of sodium chloride and 1 g of sodium citrate in 700 mL of water in a 2000-mL volumetric flask. Cautiously add 150 g of sodium hydroxide, and dissolve with shaking. Cool to room temperature, and, while stirring, cautiously add 450 mL of glacial acetic acid to the cooled solution. Cool, add 600 mL of isopropyl alcohol, dilute with water to volume, and mix: the pH of this solution is between 5.0 and 5.5.
Standard stock solution
Transfer 221 mg of sodium fluoride, previously dried at 150
Standard solutions
Dilute portions of the Standard stock solution quantitatively and stepwise with pH 5.25 Buffer to obtain 100-mL solutions having concentrations of 1, 3, 5, and 10 µg per mL.
Test solution
Transfer 1.0 g of Floxuridine to a 100-mL volumetric flask, dissolve in and dilute with pH 5.25 Buffer to volume, and mix.
Procedure
Concomitantly measure the potential (see Titrimetry
Heavy metals, Method II
Other requirements
Where the label states that Floxuridine is sterile, it meets the requirements for Sterile Solids under Injections
Assay
Dissolve about 800 mg of Floxuridine, accurately weighed, in 80 mL of dimethylformamide, and titrate with 0.1 N tetrabutylammonium hydroxide VS, determining the endpoint potentiometrically using a calomel-glass electrode system. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N tetrabutylammonium hydroxide is equivalent to 24.62 mg of C9H11FN2O5.
Auxiliary Information
Please check for your question in the FAQs before contacting USP.
USP35NF30 Page 3203
Pharmacopeial Forum: Volume No. 29(6) Page 1886
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