Sodium Acetate Solution
» Sodium Acetate Solution is an aqueous solution of Sodium Acetate. It contains not less than 97.0 percent and not more than 103.0 percent (w/w) of the labeled amount of C2H3NaO2.
Packaging and storage— Preserve in tight containers.
Identification— It responds to the tests for Sodium 191 and for Acetate 191.
pH 791: between 7.5 and 9.2, when diluted with carbon dioxide-free water to contain 5% of solids.
Insoluble matter— Dilute a quantity of Solution, equivalent to 20 g of anhydrous sodium acetate, with water to 150 mL, heat to boiling, and digest in a covered beaker on a steam bath for 1 hour. Filter through a tared filtering crucible, wash thoroughly, and dry at 105: the weight of the residue does not exceed 1 mg (0.005%).
Chloride 221 A quantity of Solution, equivalent to 1.0 g of anhydrous sodium acetate, shows no more chloride than corresponds to 0.50 mL of 0.020 N hydrochloric acid (0.035%).
Sulfate 221 A quantity of Solution, equivalent to 10 g of anhydrous sodium acetate, shows no more sulfate than corresponds to 0.50 mL of 0.020 N sulfuric acid (0.005%).
Calcium and magnesium— Dilute a quantity of Solution, equivalent to 1.0 g of anhydrous sodium acetate, to 100 mL with water. To 20 mL of this solution add 2 mL each of 6 N ammonium hydroxide, ammonium oxalate TS, and sodium phosphate TS: no turbidity is produced within 5 minutes.
Potassium— To a quantity of Solution, equivalent to 3.0 g of anhydrous sodium acetate, add 0.2 mL of sodium bitartrate TS: no turbidity is produced within 5 minutes.
Heavy metals, Method I 231 Dilute a quantity of Solution, equivalent to 2.0 g of anhydrous sodium acetate, with water to 25 mL, and use glacial acetic acid instead of 1 N acetic acid for adjustment of the pH: the limit is 0.001%.
Assay— Weigh accurately about 1 g of Solution into a 250-mL conical flask, cautiously add (in a fume hood) 2.6 mL of acetic anhydride, mix, and allow to stand for 5 minutes. Add 25 mL of glacial acetic acid and 2 drops of p-naphtholbenzein TS, and titrate with 0.1 N perchloric acid VS. Perform a blank determination, using 0.5 mL of water, and make any necessary correction. Each mL of 0.1 N perchloric acid is equivalent to 8.203 mg of C2H3NaO2.
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Monograph Daniel K. Bempong, Ph.D.
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(MDPS05) Monograph Development-Pulmonary and Steroids
USP32–NF27 Page 3562